A) \[\frac{6}{5}I\]
B) \[\frac{3}{4}I\]
C) \[\frac{3}{2}I\]
D) \[\frac{5}{4}I\]
Correct Answer: A
Solution :
Moment of inertia of disc about a tangent and parallel to its plane, \[I=\frac{M{{R}^{2}}}{4}+M{{R}^{2}}=\frac{5}{4}M{{R}^{2}}\] ... (i) Moment of inertia of disc about a tangent and perpendicular to its plane, \[=\frac{M{{R}^{2}}}{2}+M{{R}^{2}}=\frac{3}{2}M{{R}^{2}}\] \[\therefore \] \[\frac{I}{{{I}_{perpendicular}}}=\frac{\frac{5}{4}M{{R}^{2}}}{\frac{3}{2}M{{R}^{2}}}=\frac{5}{6}\] \[\therefore \] \[{{I}_{perpendicular}}=\frac{6}{5}I\]
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