A) \[0.02{}^\circ \]
B) \[0.2{}^\circ \]
C) \[3.06{}^\circ \]
D) \[30.6{}^\circ \]
Correct Answer: B
Solution :
Given,\[{{\mu }_{V}}=1.54,\] \[{{\mu }_{R}}=1.52,\] \[A={{10}^{o}}\] Angular dispersion\[(\theta )=({{\mu }_{V}}-{{\mu }_{R}})A\] \[=(1.54-1.52)\times {{10}^{o}}\] \[={{0.2}^{o}}\]
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