A) \[100{}^\circ \]
B) \[50{}^\circ \]
C) \[25{}^\circ \]
D) \[10{}^\circ \]
Correct Answer: C
Solution :
Given,\[{{f}_{o}}=100\,\,cm,\,\,{{f}_{e}}=2\,\,cm\] Visual angle subtended by moon\[(\alpha )={{0.5}^{o}}\] Visual angle subtended at eye with moons image\[(\beta )=?\] Magnifying power of telescope\[(M)=\frac{\beta }{\alpha }=\frac{{{f}_{o}}}{{{f}_{e}}}\] \[\therefore \,\,\,\,\,\,\,\beta =\alpha \,.\,\frac{{{f}_{0}}}{{{f}_{e}}}\,=0.5\,\times \,\frac{100}{2}\,={{25}^{o}}\]
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