A) \[\frac{5R}{12}\]
B) \[\frac{7R}{12}\]
C) \[\frac{3R}{12}\]
D) \[\frac{R}{12}\]
Correct Answer: A
Solution :
Resistances \[R,\,\,R\] and \[\frac{R}{2}\] are in series, their resultant resistance, \[R=R+R+\frac{R}{2}=\frac{5R}{2}\] Resistances \[R\] and \[\frac{R}{2}\] are in parallel. Their resultant resistance \[\frac{1}{R}=\frac{2}{5R}+\frac{2}{R}=\frac{2+10}{5R}\] \[R=\frac{5R}{12}\]
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