2. Solved Papers
  3. RAJASTHAN PMT

RAJASTHAN PMT Rajasthan - PMT Solved Paper-2009

  • question_answer
    An ideal heat engine working between temperature\[{{T}_{1}}\] and \[{{T}_{2}}\]has an efficiency \[\eta \] the new efficiency if temperature of both the source and sink are doubled, will be

    A)  \[\text{/2}\]                     

    B)         \[\]

    C)  \[2\,\]                 

    D)         \[\text{3}\,\]

    Correct Answer: B

    Solution :

    Efficiency of heat engine,\[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}\] when temperature of source and sink are doubled, then efficiency,                 \[n=1-\frac{2{{T}_{2}}}{2{{T}_{1}}}=1-\frac{{{T}_{2}}}{{{T}_{1}}}\]                                 \[\eta =\eta \]


You need to login to perform this action.
You will be redirected in 3 sec spinner