RAJASTHAN PMT Rajasthan - PMT Solved Paper-2009

  • question_answer
    Monochromatic light of frequency \[5\times {{10}^{14}}Hz\] travelling in vacuum enters medium of refractive index 1.5. Its wavelength in the medium is

    A)  \[4000\overset{\text{o}}{\mathop{\text{A}}}\,\]           

    B)         \[5000\overset{\text{o}}{\mathop{\text{A}}}\,\]

    C)  \[6000\overset{\text{o}}{\mathop{\text{A}}}\,\]           

    D)         \[5500\overset{\text{o}}{\mathop{\text{A}}}\,\]

    Correct Answer: A

    Solution :

    Frequency\[(f)=5\times {{10}^{4}}Hz\]. \[\therefore \]  Wavelength of light\[(\lambda )=\frac{c}{f}=\frac{3\times {{10}^{8}}}{5\times {{10}^{14}}}\]                     \[=6\times {{10}^{-7}}\]                 \[m=6000\,\,\overset{\text{o}}{\mathop{\text{A}}}\,\] \[\therefore \]Wavelength in medium of refractive index                 \[\lambda =\frac{\lambda }{\mu }\]                     \[=\frac{6000}{1.5}\]                     \[=4000\,\,\overset{\text{o}}{\mathop{\text{A}}}\,\]


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