A) \[NaCl\]
B) \[NaBr\]
C) \[NaI\]
D) \[{{K}_{2}}Cr{{O}_{4}}\]
Correct Answer: D
Solution :
\[NaCl+AgN{{O}_{3}}\xrightarrow{{}}\underset{white\,\,ppt.}{\mathop{AgCl\downarrow }}\,+NaN{{O}_{3}}\] \[Nal+AgN{{O}_{3}}\xrightarrow{{}}\underset{light\,\,yellow\,\,ppt.}{\mathop{AgBr\downarrow }}\,+NaN{{O}_{3}}\] \[NaI+AgN{{O}_{3}}\xrightarrow{{}}\underset{yellow\,\,ppt.}{\mathop{AgI\downarrow }}\,+NaN{{O}_{3}}\] \[{{K}_{2}}Cr{{O}_{4}}+2AgN{{O}_{3}}\xrightarrow{{}}\underset{red\,\,ppt.}{\mathop{A{{g}_{2}}Cr{{O}_{4}}}}\,+2KN{{O}_{3}}\]
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