RAJASTHAN PMT Rajasthan - PMT Solved Paper-2009

  • question_answer
    Bond order of \[{{N}_{2}}\] molecule is

    A) \[3\]                                     

    B)        \[2\]                     

    C)        \[1\]                                     

    D)        \[0\]

    Correct Answer: A

    Solution :

    The molecular configuration of \[{{N}_{2}}\] is \[\sigma 1{{s}^{2}},\,\overset{*}{\mathop{\sigma }}\,1{{s}^{2}}\sigma 2{{s}^{2}}\overset{*}{\mathop{\sigma }}\,2{{s}^{2}}\left\{ \begin{matrix}    \pi 2p_{y}^{2}  \\    \pi 2p_{x}^{2}  \\ \end{matrix} \right.\overset{*}{\mathop{\sigma }}\,2{{p}_{z}}^{2}\]                                          \[\left\{ \begin{matrix}    \overset{*}{\mathop{\pi }}\,2{{p}_{y}}  \\    \overset{*}{\mathop{\pi }}\,2{{p}_{x}}  \\ \end{matrix} \right.\overset{*}{\mathop{\sigma }}\,2{{p}_{z}}\]                 number of bonding electrons \[Bond\,\,order=\frac{-number\,\,of\,\,antibonding\,\,electrons}{2}\] \[=\frac{10-4}{2}\] \[\therefore \]  \[=3\]


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