A) \[3\,\,mL\]
B) \[12\,\,mL\]
C) \[24\,\,mL\]
D) \[48\,\,mL\]
Correct Answer: D
Solution :
\[\underset{\begin{smallmatrix} 1\,\,mol \\ 12\,\,mL \end{smallmatrix}}{\mathop{{{C}_{4}}{{H}_{10}}}}\,+\frac{13}{2}{{O}_{2}}\xrightarrow{{}}\underset{\begin{smallmatrix} 4\,\,mol \\ 12\times 4=48\,\,mL \end{smallmatrix}}{\mathop{4C{{O}_{2}}}}\,+5{{H}_{2}}O\]
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