A) nylon 6, 6
B) nylon 7, 6
C) nylon 6, 5
D) nylon 9, 7
Correct Answer: A
Solution :
\[\underset{adpric\,\,acid}{\mathop{nHO-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-{{(C{{H}_{2}})}_{4}}}}\,-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-OH\] \[+nh-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{N}}\,-{{(C{{H}_{2}})}_{6}}-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{N}}\,-H\xrightarrow{-2n{{H}_{2}}O}\] \[\underset{nylon\,\,6,\,\,6}{\mathop{\left[ -\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-{{(C{{H}_{2}})}_{4}}+\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{N}}\,-{{(C{{H}_{2}})}_{6}}-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{N}}\,- \right]}}\,\]
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