RAJASTHAN PMT Rajasthan - PMT Solved Paper-2009

  • question_answer
    Percentage of oxygen in phenol is

    A) \[17.02\]                             

    B) \[15.2\]               

    C)        \[16\]                   

    D)        \[15\]

    Correct Answer: A

    Solution :

    Molecular formula of phenol\[={{C}_{6}}{{H}_{5}}OH\] Molecular weight\[=94\,\,u\] \[%\,\,of\,\,oxygen=\frac{weight\,\,of\,\,oxygen}{molecular\,\,weight}\times 100\]                           \[=\frac{16}{94}\times 100\] \[\therefore \,\,%\]of oxygen\[=17.02\]


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