A) \[[L{{T}^{-1}}]\]
B) \[[{{L}^{-1}}T]\]
C) \[[{{L}^{-}}^{2}{{T}^{2}}]\]
D) \[[{{L}^{2}}{{T}^{-2}}]\]
Correct Answer: D
Solution :
\[c=\frac{1}{\sqrt{{{\mu }_{0}}{{\varepsilon }_{0}}}}\Rightarrow \frac{1}{{{\mu }_{0}}{{\varepsilon }_{0}}}={{c}^{2}}=[{{L}^{2}}{{T}^{-2}}]\]
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