RAJASTHAN PMT Rajasthan - PMT Solved Paper-2010

  • question_answer
    A sphere of mass m is tied to end of a string of length\[l\]and rotated through the other end along a horizontal circular path with speed v. The work done in full horizontal circle is

    A)  zero                                     

    B)  \[\left( \frac{m{{v}^{2}}}{l} \right)2\pi l\]

    C)  \[mg.\,2\pi l\]                  

    D)         \[\left( \frac{m{{v}^{2}}}{l} \right)(l)\]

    Correct Answer: A

    Solution :

    Work done by centripetal force in uniform circular motion is always equal to zero.


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