RAJASTHAN PMT Rajasthan - PMT Solved Paper-2010

  • question_answer
    The fraction of a floating object of volume\[{{V}_{0}}\] and density\[{{d}_{0}}\]above the surface of liquid of density\[d\] will be

    A)  \[\frac{{{d}_{0}}}{d}\]                                  

    B)  \[\frac{d{{d}_{0}}}{d+{{d}_{0}}}\]

    C)  \[\frac{d-{{d}_{0}}}{d}\]              

    D)         \[\frac{d{{d}_{0}}}{d-{{d}_{0}}}\]

    Correct Answer: C

    Solution :

    For the floatation\[{{V}_{0}}{{d}_{0}}g={{V}_{in}}dg\] \[\Rightarrow \]               \[{{V}_{in}}={{V}_{0}}\frac{{{d}_{0}}}{d}\] \[\therefore \]  \[{{V}_{out}}={{V}_{0}}-{{V}_{in}}={{V}_{0}}-{{V}_{0}}\frac{{{d}_{0}}}{d}\]                 \[={{V}_{0}}\left[ \frac{d-{{d}_{0}}}{d} \right]\] \[\Rightarrow \]               \[\frac{{{V}_{out}}}{{{V}_{0}}}=\frac{d-{{d}_{0}}}{d}\]


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