A) Photographic plates are sensitive to infrared rays
B) Photographic plates are sensitive to ultraviolet rays
C) Infra red rays are invisible but can cast shadows like visible light
D) Infrared photons have more energy than photons of visible light
Correct Answer: D
Solution :
Energy\[E\propto \frac{1}{Wavelength\lambda }\] We have \[{{\lambda }_{\text{infrared}}}>{{\lambda }_{\text{visible}}}\] \[\therefore \] \[{{E}_{\text{infrared}}}<{{E}_{\text{visible}}}\]
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