question_answer

Which of the following represents the given mode of hybridization\[s{{p}^{2}}-s{{p}^{2}}-sp-sp\] from left to right?

A) \[{{H}_{2}}C=CH-C\equiv N\]

B)        \[HC\equiv C-C\equiv CH\]

C)        \[{{H}_{2}}C=C=C{{H}_{2}}\]

D)         

Correct Answer: A

Solution :

(a)\[\underset{s{{p}^{2}}}{\mathop{{{H}_{2}}C}}\,=\underset{s{{p}^{2}}}{\mathop{CH}}\,=\underset{sp}{\mathop{C}}\,\equiv \underset{sp}{\mathop{N}}\,\] (b)\[\underset{sp}{\mathop{HC}}\,\equiv \underset{sp}{\mathop{C}}\,-\underset{sp}{\mathop{C}}\,\equiv \underset{sp}{\mathop{CH}}\,\] (c)\[\underset{s{{p}^{2}}}{\mathop{{{H}_{2}}C}}\,=\underset{sp}{\mathop{C}}\,=\underset{sp}{\mathop{C}}\,=\underset{s{{p}^{2}}}{\mathop{C{{H}_{2}}}}\,\] (d) Hence, \[{{H}_{2}}C=CH-C\equiv N\] represents the \[s{{p}^{2}}-s{{p}^{2}}-sp-sp\]hybridisation from left to right.