RAJASTHAN PMT Rajasthan - PMT Solved Paper-2010

  • question_answer
    Gypsum on heating to \[390\,\,K\] gives

    A) \[CaS{{O}_{4}}\cdot 2{{H}_{2}}O\]          

    B)        \[CaS{{O}_{4}}\]

    C)        \[CaS{{O}_{4}}\cdot \frac{1}{2}{{H}_{2}}O\]        

    D)        \[S{{O}_{3}}\]and\[CaO\]

    Correct Answer: C

    Solution :

    \[\underset{Gypsum}{\mathop{2CaS{{O}_{4}}}}\,\cdot 2{{H}_{2}}O\xrightarrow{393\,\,K}\underset{Plaster\,\,of\,\,Paris}{\mathop{2CaS{{O}_{4}}\cdot \frac{1}{4}{{H}_{2}}O}}\,\]                                                                 \[+3{{H}_{2}}O\]


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