A) \[299.6\,\,K\]
B) \[{{0}^{o}}C\]
C) \[273\,\,K\]
D) \[{{10}^{o}}C\]
Correct Answer: A
Solution :
\[28g{{N}_{2}}=1\,\,mole\]of\[{{N}_{2}}\]. Applying\[pV=nRT\], \[2.46\times 10=1\times 0.0821\times T\]. This gives \[T=299.6\,\,K\]
You need to login to perform this action.
You will be redirected in
3 sec
