A) \[sp-\]hybridized
B) \[s{{p}^{3}}d-\]hybridized
C) \[s{{p}^{2}}-\]hybridized
D) \[s{{p}^{3}}-\]hybridized
Correct Answer: A
Solution :
\[\underset{sp}{\mathop{O=C=O}}\,\] In\[C{{O}_{2}}\], carbon is in \[sp-\]hybridized state.
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