A) \[4\alpha \]and\[1\beta \]
B) \[3\alpha \]and\[7\beta \]
C) \[8\alpha \]and\[1\beta \]
D) \[4\alpha \]and\[7\beta \]
Correct Answer: A
Solution :
In the reaction \[_{90}T{{h}^{228}}{{\xrightarrow{{}}}_{83}}B{{i}^{212}}\] (Here, \[x\]and \[y\] are the number of \[\alpha \] and \[\beta -\]particles) \[\because \] \[228-4x=212\] \[-4x=212-228\] \[-4x=-16\] and \[90-2\times 4+y=83\] \[82+y=83\] \[y=83-82\] \[y=1\] Hence \[4\alpha \] and \[1\beta \] particles are emitted in the nuclear reaction.
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