A) 80 cm/s
B) 40 cm/s
C) 20 cm/s
D) 5 cm/s
Correct Answer: A
Solution :
In now of fluids in a tube \[{{v}_{1}}r_{1}^{2}={{v}_{2}}r_{2}^{2}\] \[20\times {{(0.2)}^{2}}={{v}_{2}}\times {{(0.1)}^{2}}\] \[{{v}_{2}}=\frac{20\times {{(0.2)}^{2}}}{{{(0.1)}^{2}}}\] \[{{v}_{2}}=80\,\,cm/s\]
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