RAJASTHAN PMT Rajasthan - PMT Solved Paper-2011

  • question_answer
    A charge +Q is placed at the centre of a spherical surface of radius R. Another charge -Q/2 is placed at a distance of R/2 from the centre of the surface. A third charge -Q/2 is at a distance 3R/2 from the centre. The electrostatic flux linked with the surface is

    A)  zero                                     

    B) \[\frac{Q}{2{{\varepsilon }_{0}}}\]

    C) \[\frac{3Q}{2{{\varepsilon }_{0}}}\]        

    D)         \[\frac{2Q}{{{\varepsilon }_{0}}}\]

    Correct Answer: B

    Solution :

    \[\phi =\frac{Q-Q/2}{{{\varepsilon }_{0}}}\]                 \[\phi =\frac{2Q-Q}{2{{\varepsilon }_{0}}}\]                                 \[\phi =\frac{Q}{2{{\varepsilon }_{0}}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner