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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2011

  • question_answer
    If the ionization potential of hydrogen atom is 13.6 eV, its energy in the n=3 is approximately

    A)  -1.14 eV                             

    B)  -1.51 eV

    C)  -3.4 eV                

    D)         -4.53 eV

    Correct Answer: B

    Solution :

    \[E=-\frac{-13.6}{{{(3)}^{2}}}\]                 Given,\[n=3\]                            \[E=\frac{-13.6}{{{(3)}^{2}}}\]                 \[E=\frac{-13.6}{9}=-1.51\,\,eV\]


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