question_answer

When propanoic acid is treated with aqueous sodium bicarbonate, \[C{{O}_{2}}\] is liberated. The carbon of \[C{{O}_{2}}\] comes from

A)  methyl group

B)  carboxylic acid group

C)  methylene group

D)  bicarbonate

Correct Answer: D

Solution :

During the reaction of carboxylic acids with weaker base \[NaHC{{O}_{3}}\], the \[C{{O}_{2}}\] evolved comes from \[NaHC{{O}_{3}}\] and not from the carboxylic acid as shown below