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Uttarakhand PMT Uttarakhand PMT Solved Paper-2004

  • question_answer
    In an equilateral triangle ABC \[{{F}_{1}}\]\[{{F}_{2}}\] and \[{{F}_{3}}\] are three forces acting along the sides AB, BC and AC as shown in the given figure. What should be the magnitude of \[{{F}_{3}}\] so that the total torque about O is zero?

    A)  2 N          

    B)  4 N

    C)  6 N          

    D)  8 N

    Correct Answer: C

    Solution :

     The total torque about O is given by or      \[\tau ={{F}_{1}}d+{{F}_{2}}d-{{F}_{3}}d\] \[\Rightarrow \] \[{{F}_{3}}={{F}_{1}}+{{F}_{2}}\] \[=4+2\] \[=6N\] Here, d is the perpendicular distance of O from every side of the equilateral triangle.


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