Uttarakhand PMT Uttarakhand PMT Solved Paper-2004

  • question_answer
    The rotational kinetic energy of a body is \[{{K}_{rot}}\] and its moment of inertia is J. The angular momentum of body is :

    A) \[I{{K}_{rot}}\]

    B) \[2\sqrt{I{{K}_{rot}}}\]

    C)  \[\sqrt{21\,{{K}_{rot}}}\]

    D)  \[2\,I{{K}_{rot}}\]

    Correct Answer: C

    Solution :

     The rotational kinetic energy of a body is given by \[{{K}_{rot}}=\frac{1}{2}I{{\omega }^{2}}\] \[\Rightarrow \] \[I{{\omega }^{2}}=2{{K}_{rot}}\] \[\Rightarrow \] \[\omega =\sqrt{\frac{2{{K}_{rot}}}{I}}\] Angular momentum of body is given by \[J=I\omega =I\times \sqrt{\frac{2{{K}_{rot}}}{I}}\] \[=\sqrt{2{{K}_{rot}}I}\]


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