A) 1000 K
B) 1189 K
C) 2000 K
D) 2378 K
Correct Answer: A
Solution :
Total surface area of square plate is given by \[=2\times {{(10\times {{10}^{-2}})}^{2}}{{m}^{2}}\] \[=2\times {{10}^{-2}}{{m}^{2}}\] The rate of radiated energy is given by \[E=e\sigma A{{T}^{4}}\] \[\Rightarrow \] \[{{T}^{4}}=\frac{E}{e\sigma A}\] \[\Rightarrow \] \[{{T}^{4}}=\frac{1134}{1\times 5.67\times {{10}^{-8}}\times 2\times {{10}^{-2}}}\] \[={{10}^{12}}\] \[\therefore \] \[T={{10}^{3}}K\] \[=1000K\]
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