A) \[1.4\times {{10}^{-21}}g\]
B) \[3.7\times {{10}^{-23}}g\]
C) \[4.1\times {{10}^{23}}g\]
D) \[4.7\times {{10}^{23}}g\]
Correct Answer: A
Solution :
The mass of a compound \[=\frac{molecular\text{ }mass}{Ayogadros\text{ }number}\] Molecular mass of\[{{C}_{60}}{{H}_{122}}\] \[=(12\times 60+122)\] Avogadros number \[=6.023\times {{10}^{23}}\] \[\therefore \] mass\[=\frac{842}{6.023\times {{10}^{23}}}\] \[=1.4\times {{10}^{-21}}g\]
You need to login to perform this action.
You will be redirected in
3 sec
