Uttarakhand PMT Uttarakhand PMT Solved Paper-2005

  • question_answer
    The number of sodium atoms present in 2.3 g of sodium are:

    A)  \[6.023\times {{10}^{22}}\]       

    B)  \[6.012\times {{10}^{23}}\]

    C)  \[2.323\times {{10}^{20}}\]      

    D)  \[2.323\times {{10}^{23}}\]

    Correct Answer: A

    Solution :

     The atomic weight of sodium = 23 \[\therefore \]gram atomic weight of sodium = 23 g \[\because \] 23   g   of   sodium   contains\[6.023\times {{10}^{23}}\]atoms \[\therefore \]2.3 g sodium contains atoms \[=\frac{6.023\times {{10}^{23}}\times 2.3}{23}\] \[=6.023\times {{10}^{22}}\]atoms


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