A) \[1\times {{10}^{-6}}\]
B) \[2\times {{10}^{-6}}\]
C) \[2\times {{10}^{-7}}\]
D) \[4\times {{10}^{-7}}\]
Correct Answer: D
Solution :
The solubility product of \[AgBr[A{{g}^{+}}][B{{r}^{-}}]\] \[=4\times {{10}^{-13}}\]moles/litre The\[A{{g}^{+}}\]ion concentration \[=1\times {{10}^{-6}}\]moks/litre \[\therefore \] \[B{{r}^{-}}=\frac{solubility\text{ }product\text{ }of\text{ }AgBr}{[A{{g}^{+}}]}\] \[=\frac{4\times {{10}^{-13}}}{1\times {{10}^{-6}}}\] \[=4\times {{10}^{-7}}\]moles/litre
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