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Uttarakhand PMT Uttarakhand PMT Solved Paper-2006

  • question_answer
    A particle is executing two different simple harmonic motions, mutually perpendicular, of  different amplitudes and having phas difference of \[\frac{\pi }{2}.\]The path of the particle will be:

    A)  circular           

    B)  straight line

    C)  paraboilic        

    D)  elliptical

    Correct Answer: D

    Solution :

     As the different amplitudes are mutually perpendicular which have phase difference of \[\frac{\pi }{2}\]. Therefore, particle will follow elliptical path.


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