A) 30 kV
B) 50 kV
C) 80 kV
D) 60 kV
Correct Answer: A
Solution :
From the formula \[eV=h\frac{c}{\lambda }\] \[V=\frac{hc}{e\lambda }=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{1.6\times {{10}^{-19}}\times 0.4125\times {{10}^{-10}}}\] \[=30\times {{10}^{3}}volt=30\,kV\]
You need to login to perform this action.
You will be redirected in
3 sec
