A) 516 m/s
B) 450 m/s
C) 310 m/s
D) 746 m/s
Correct Answer: A
Solution :
We know that rms .speed is directly proportional to square root of temperature \[{{v}_{rms}}\propto \sqrt{T}\] Hence \[\frac{{{v}_{rms(1)}}}{{{v}_{rms(2)}}}=\sqrt{\frac{{{T}_{1}}}{{{T}_{2}}}}\] \[\frac{400}{{{v}_{rms(2)}}}=\frac{\sqrt{27+273}}{\sqrt{227+273}}\] \[=\sqrt{\frac{300}{500}}\] \[{{v}_{rms(2)}}=\sqrt{\frac{500}{300}}\times 400\] \[=1.29\times 400\] \[=516.39\,m/s\] \[\approx 516m/s\]
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