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Uttarakhand PMT Uttarakhand PMT Solved Paper-2006

  • question_answer
    How much chlorine will be liberated on passing one ampere current for 30 minute through\[NaCl\]solution?

    A)  0.66 mole       

    B)  0.33 mole

    C)  0.66g           

    D)  0.33g

    Correct Answer: C

    Solution :

     According to Faradays law: \[w=zit\] \[w=\frac{E}{96500}\times i\times t\] Or \[w=\frac{35.5\times 1\times 30\times 60}{96500}\] \[\Rightarrow \] \[=0.662g\] so, 0.662 g chlorine is liberated.


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