A) \[K=[Ar]\text{ }4{{s}^{1}}\]
B) \[Cr=[Ar]\text{ }3{{d}^{5}},4{{s}^{1}}\]
C) \[Cr=[Ar]\text{ }3{{d}^{4}},\text{ }4{{s}^{2}}\]
D) \[Cu=[Ar]\text{ }3{{d}^{10}},4{{s}^{1}}\]
Correct Answer: C
Solution :
The correct configurations of\[K,Cu\]and Cr are \[[Ar]4{{s}^{1}},[Ar]3{{d}^{10}}4{{s}^{1}},[Ar]3{{d}^{5}}4{{s}^{1}}\]respectively. As half filled and completely filled d orbitals are more stable, hence, in case of Cr and Cu one electron shirts from 45 orbital to 3d orbital to give them stable electronic configuration.
You need to login to perform this action.
You will be redirected in
3 sec
