A) 10, 6, 2
B) 11, 3, 7
C) 10, 3, 7
D) 10, 4, 7
Correct Answer: B
Solution :
Given\[O{{H}^{-}}\]ion cone. is\[{{10}^{-3}}M\] we know, \[[{{H}^{+}}][O{{H}^{-}}]={{10}^{-14}}\] or \[[{{H}^{+}}]=\frac{{{10}^{-14}}}{{{10}^{-3}}}\] or \[[{{H}^{+}}]={{10}^{-11}}\] \[\because \] \[pH=-\log [{{H}^{+}}]-\log [{{10}^{-11}}]\] \[pH=11\] Similarly pH of\[HCl\]is 3 and pH of\[NaCl\]is 7.
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