A) \[H{{e}_{2}}\]
B) \[{{N}_{2}}\]
C) \[{{H}_{2}}\]
D) \[{{F}_{2}}\]
Correct Answer: A
Solution :
Configuration of \[H{{e}_{2}}:\sigma 1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}}\] Bond order in \[H{{e}_{2}}=\frac{1}{4}[{{N}_{b}}-{{N}_{a}}]=\frac{1}{2}[2-2]=0\] Hence,\[H{{e}_{2}}\]molecules does not exist.
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