Uttarakhand PMT Uttarakhand PMT Solved Paper-2006

  • question_answer
    Freundlich adsorption isotherm is:

    A)  \[\frac{x}{m}=k{{p}^{1/n}}\]

    B)  \[x=mk{{p}^{1/n}}\]

    C)  \[\frac{x}{m}=k{{p}^{-n}}\]         

    D)  all of these

    Correct Answer: A

    Solution :

     Freundlich adsorption isotherm is\[\frac{x}{m}=k{{p}^{1/n}}\] where,\[x\]is the mass of adsorbate, \[m\]is the mass of adsorbent


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