A) Ultraviolet rays
B) Radiowaves
C) Visible radiation
D) X-rays
Correct Answer: B
Solution :
\[n=1\text{ }GHz={{10}^{9}}Hz\] \[\therefore \] \[\lambda =\frac{c}{n}=\frac{3\times {{10}^{8}}}{{{10}^{9}}}=\frac{3}{10}\] \[\Rightarrow \] \[\lambda =0.3m=30\,cm\] (radiowaves)
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