Uttarakhand PMT Uttarakhand PMT Solved Paper-2007

  • question_answer
    What is maximum height of a stone thrown vertically upward, if its velocity is halved in 1.5s? \[(g=10m/{{s}^{2}})\]

    A)  20m          

    B)  25m

    C)  30m          

    D)  45m

    Correct Answer: D

    Solution :

     According to question \[v=\frac{u}{2}=u-gt=u-\frac{3}{2}g\]as\[t=1.5s\] \[\Rightarrow \] \[u=30\text{ }m/s\] Again         \[h=\frac{{{u}^{2}}}{2g}\] \[\Rightarrow \] \[h=\frac{30\times 30}{2\times 10}\] \[\Rightarrow \] \[h=45\,m\]


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