A) unity
B) \[1-\frac{Pb}{RT}\]
C) \[1+\frac{Pb}{RT}\]
D) zero
Correct Answer: C
Solution :
\[P+\frac{a}{{{V}^{2}}}(V-d)=RT\] At high pressure b can not be neglected in comparison to V. Further though V becomes small,\[\frac{a}{{{V}^{2}}}\]is large but as P is very high,\[\frac{a}{{{V}^{2}}}\]. Can be neglected in comparison to P. Hence, \[P(V-d)=RT\]or \[PV=RT+Pb\] or \[\frac{PV}{RT}=1+\frac{Pb}{RT}\]ie, \[z=1+\frac{Pb}{RT}\]
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