A) \[{{10}^{3}}J\]
B) \[{{10}^{4}}J\]
C) \[2\times {{10}^{3}}J\]
D) \[4\times {{10}^{4}}J\]
Correct Answer: B
Solution :
\[v=u+at\] \[\therefore \] \[20=0+a\times 10\] \[20=a\times 10\] \[a=2m/{{s}^{2}}\] Now, \[s=ut+\frac{1}{2}a{{t}^{2}}\] \[s=0+\frac{1}{2}\times 2\times 10\times 10\] \[s=100\,m\] Hence, work done \[W=F\times s\] or \[W=ma\times s\] \[\therefore \] \[W=50\times 2\times 100\] \[W=10000\] \[={{10}^{4}}J\]
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