A) \[1:1\]
B) \[1:2\]
C) \[2:1\]
D) None of these
Correct Answer: B
Solution :
100 mL of \[1\text{ }M\text{ }AgN{{O}_{3}}=0.1\text{ }mol\text{ }AgN{{O}_{3}}\] 100 mL of\[1M\text{ }CuS{{O}_{4}}=0.1\text{ }mol\text{ }CuS{{O}_{4}}\] \[\underset{\begin{smallmatrix} 2\,mol \\ 0.1\,mol \end{smallmatrix}}{\mathop{2AgN{{O}_{3}}}}\,+\underset{\begin{smallmatrix} 1\,mol \\ 0.05\,mol \end{smallmatrix}}{\mathop{{{H}_{2}}S}}\,\xrightarrow[{}]{{}}A{{g}_{2}}S+2HN{{O}_{3}}\] \[\underset{\begin{smallmatrix} 1\,mol \\ 0.1\,mol \end{smallmatrix}}{\mathop{CuS{{O}_{4}}}}\,+\underset{\begin{smallmatrix} 1\,mol \\ 0.1\,mol \end{smallmatrix}}{\mathop{{{H}_{2}}S}}\,\xrightarrow[{}]{{}}CuS+{{H}_{2}}S{{O}_{4}}\] \[\therefore \] Ratio of the amounts of H^S obtained \[=0.05:0.1=1:2\]
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