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Uttarakhand PMT Uttarakhand PMT Solved Paper-2008

  • question_answer
    The number of\[\alpha -\]and\[\beta -\]particles emitted in nuclear reaction\[_{90}T{{h}^{228}}{{\xrightarrow[{}]{{}}}_{83}}B{{i}^{212}}\]are respectively

    A)  4, 1          

    B)  3, 7

    C)  8, 1          

    D)  4, 7

    Correct Answer: A

    Solution :

     \[_{90}T{{h}^{228}}{{\xrightarrow[{}]{{}}}_{83}}B{{i}^{212}}+x_{2}^{4}\alpha +y_{-1}^{0}\beta \] \[228=212+4x\] or\[4x=16\text{ }or\text{ }x=4\] \[90=83+2x-y=83+8-y\text{ }or\,y=1\]


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