Uttarakhand PMT Uttarakhand PMT Solved Paper-2009

  • question_answer
    What is the current through an ideal \[pn\]-junction diode shown in figure below?

    A)  Zero         

    B)  10mA

    C)  20mA        

    D)  50mA

    Correct Answer: C

    Solution :

     The potential of p-side is more positive than that of n-side, hence, diode is in forward biasing. In forward biasing current flow is possible and\[I=\frac{V}{R}\] \[=\frac{(3-1)}{100}20\,mA\]


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