Uttarakhand PMT Uttarakhand PMT Solved Paper-2009

  • question_answer
    The average power dissipation in pure inductance is                           

    A)  \[\frac{1}{2}L{{I}^{2}}\]

    B)  \[2L{{I}^{2}}\]

    C)  \[\frac{1}{4}L{{I}^{2}}\]

    D)  \[\text{Zero}\]

    Correct Answer: D

    Solution :

     The average of instantaneous power in an AC circuit over a full cycle is called average power. Its unit is watt. \[{{P}_{av}}={{V}_{rms}}{{I}_{rms}}\cos \phi \] In a pure inductance, phase difference between voltage and current \[\phi =90{}^\circ \]. Power factor \[\cos \phi =0\] \[\therefore \] Power \[P=0\]


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