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Uttarakhand PMT Uttarakhand PMT Solved Paper-2009

  • question_answer
    The potential energy of a charged parallel plate capacitor is \[{{U}_{0.}}\] If a slab of dielectric constant is inserted between the places, then the new potential energy will be

    A)  \[\frac{{{U}_{0}}}{K}\]

    B)  \[{{U}_{0}}{{K}^{2}}\]

    C)  \[\frac{{{U}_{0}}}{{{K}^{2}}}\]

    D)  \[U_{0}^{2}\]

    Correct Answer: A

    Solution :

     When a dielectric slab of dielectric constant K is inserted between the plates of charged parallel plate capacitor, then capacity becomes\[C=KC\] potential becomes \[V=\frac{V}{K}\] and energy \[U=\frac{U}{K}\]


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