Uttarakhand PMT Uttarakhand PMT Solved Paper-2009

  • question_answer
    If the solubility of calcium fluoride in pure water is x mol/L, its solubility product is

    A)  \[\sqrt{2}x\]           

    B)  \[2{{x}^{2}}\]

    C)  \[4{{x}^{3}}\]            

    D)  \[{{x}^{2}}\]

    Correct Answer: C

    Solution :

     \[\underset{x}{\mathop{Ca{{F}_{2}}}}\,\rightleftharpoons \underset{x}{\mathop{C{{a}^{2+}}}}\,+\underset{2x}{\mathop{2{{F}^{-}}}}\,\] \[{{K}_{sp}}=[C{{a}^{2+}}]{{[2{{F}^{-}}]}^{2}}\] \[=(x){{(2x)}^{2}}=4{{x}^{3}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner