A) 48.9 atm
B) 4.89 atm
C) 0.489 atm
D) 489 atm
Correct Answer: B
Solution :
\[pV=nRT\] or \[p=\frac{nRT}{V}\] \[=\frac{0.60\times 0.0821\times 298}{3}\] \[=4.89\text{ }atm\]
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