A) 2.5
B) 5
C) 50
D) 10s
Correct Answer: D
Solution :
\[90=10{{\log }_{10}}\left( \frac{{{I}_{2}}}{{{I}_{0}}} \right)\] \[\Rightarrow \] \[\frac{{{I}_{1}}}{{{I}_{0}}}={{10}^{4}}\] ...(i) Again, \[40=10{{\log }_{10}}\left( \frac{{{I}_{2}}}{{{I}_{0}}} \right)\] \[\Rightarrow \] \[\frac{{{I}_{2}}}{{{I}_{0}}}={{10}^{4}}\] ...(ii) From Eqs. (i) and (ii), we get \[\frac{{{I}_{1}}}{{{I}_{2}}}={{10}^{5}}\]
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